In Criminal Defense LawyersRegion Los Angeles regional results

What are the best criminal defense lawyers in Los Angeles, CA?

EditionNov 12, 2026Asked on 5 AI surfacesv5.0

AI Visibility Ranking

Brands ordered by GenRank score for this question.

DirectionalQuestion-level figures rest on at most 5 answers per brand, so treat them as direction, not a verdict; the category ranking is the number to judge by. Scores are for the week of 2026-11-08.

RankBrandNamed byScore
1Manshoory Law Group4/569.8
2The Rodriguez Law Group3/544.5
3Stephen G. Rodriguez & Partners3/537.3
4CBS Law1/530.0
5Perlman & Cohen Los Angeles Criminal Lawyers1/526.4
6Dmitry Gorin2/524.2
7Hurwitz Law Group1/521.9
8Werksman Jackson & Quinn2/520.9
9Michael Kraut1/516.0
10Nina Marino2/515.4

Sources these answers cited

The sites each surface's answer cited this week. The logos are the surfaces that cited the site.

SourceCited by
doylesguide.comLeading Criminal Defense Lawyers – Los Angeles, 20263 surfaces
attorneys.superlawyers.comBest Los Angeles, CA Criminal Defense Attorneys | Super Lawyers2 surfaces
expertise.comBest Criminal Defense Lawyers Los Angeles, CA - Expertise.com2 surfaces
avvo.comTop Rated Los Angeles, CA Criminal Defense Lawyers - Avvo.com1 surfaces
bestlawyers.comMark J. Werksman - Criminal Defense: General Practice Lawyer - Los Angeles, CA1 surfaces
calbar.ca.govpublic · Find Legal Professionals | The State Bar of California1 surfaces
egattorneys.comDmitry Gorin Attorney Los Angeles | Eisner Gorin LLP1 surfaces
forbes.commedia · Best Criminal Defense Lawyers Los Angeles, CA - Forbes1 surfaces
justia.comBest Criminal Lawyers in Los Angeles County, CA1 surfaces
lawyers.comLos Angeles, CA Criminal Defense Law Firms & Lawyers1 surfaces
lawyers.findlaw.comBest Criminal Defense Lawyers in Los Angeles, CA | FindLaw1 surfaces
ontoplist.comTop Criminal Defense Lawyers in Los Angeles - OnToplist1 surfaces

3 more

Rank trend

Rank trends are drawn once two weekly editions under the same methodology exist. Only the first edition is in so far.